Answer
Please see the graph.
Work Step by Step
$x^2 +y^2 \le 9$
This is the equation of a circle with radius 3. If a point is a valid solution to the inequality, then it will be inside the circle. We pick the point $(4,1)$ to determine if this is part of the solution set.
$x^2 +y^2 \le 9$
$4^2 +1^2 \le 9$
$16 + 1 \le 9$
$17 \le 9$ (false)
This point is outside the circle, so it is not part of the shaded region.