Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Section 13.2 - The Ellipse and the Hyperbola - Exercise Set - Page 941: 56

Answer

A $\rightarrow$ $a^{2}$ = 36 , $b^{2}$ = 13 B $\rightarrow$ $a^{2}$ = 4 , $b^{2}$ = 4 C $\rightarrow$ $a^{2}$ = 25 , $b^{2}$ = 16 D $\rightarrow$ $a^{2}$ = 25 , $b^{2}$ = 39 E $\rightarrow$ $a^{2}$ = 17 , $b^{2}$ = 18 F $\rightarrow$ $a^{2}$ = 36 , $b^{2}$ = 36 G $\rightarrow$ $a^{2}$ = 16 , $b^{2}$ = 65 H $\rightarrow$ $a^{2}$ = 144 , $b^{2}$ = 140

Work Step by Step

Standerd form of a: Ellipse: $\frac{x^{2}}{a^{2}}$ + $\frac{y^{2}}{b^{2}}$ = 1 Hyperbola: $\frac{x^{2}}{a^{2}}$ - $\frac{y^{2}}{b^{2}}$ = 1 Simplifying, to know the values of $a^{2}$ and $b^{2}$, $\rightarrow$ value/number under $x^{2}$ is $a^{2}$ $\rightarrow$ value/number under $y^{2}$ is $b^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.