Answer
It is a hyperbola.
See Graph I for the equation.
Work Step by Step
For $\frac{x^2}{16} - \frac{y^2}{4} = 1$,
it is a hyperbola with center at (0, 0) and x-intercepts at $\pm4$.
See Graph I for the equation.
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 13 - Section 13.2 - Integrated Review - Graphing Conic Sections - Page 943: 6
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