## Algebra: A Combined Approach (4th Edition)

$(x-2)^{2}$ + $(y-3)^{2}$ = 36
The proper form of a circle is $(x-h)^{2}$ + $(y-k)^{2}$ = $r^{2}$, where (h,k) is the center of the circle and r is its radius. Therefore, a circle with a center at (2,3) and a radius of 6 would yield the equation $(x-2)^{2}$ + $(y-3)^{2}$ = 36.