Answer
$y=-\frac{2}{125}(x−50)^2+40$
Work Step by Step
$y=a(x−h)^2+k$
$y=a(x−50)^2+40$
The point (0,0) represents the end of the bridge.
$0=a(0−50)^2+40$
−40=2500a
$a=-\frac{2}{125}$
$y=-\frac{2}{125}(x−50)^2+40$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 13 - Section 13.1 - The Parabola and the Circle - Exercise Set - Page 929: 60
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