Answer
a). The radius is 75m
b). 15m from the ground
c). 90m from the ground
d). (0,9.4868) with a radius of 90m, we must note that the axes include the ground and not just the wheel.
e). $x^2+ (y-9.4868)^2=90$
Work Step by Step
a). The radius of a circle is half its diameter, so $r=\frac{d}{2}=\frac{150}{2}=75m$
b). subtract the diameter of the wheel from its height: $165m-150m=15m$
c). The center of the wheel corresponds to the radius i.e. 75m. Add this value to the height above the ground of the wheel: $15m+75m=90m$
d). We can see this by plotting the equation corresponding to the co-ordinates (0,9.4868).
e). See the graph attached below, it is the equation $x^2+ (y-9.4868)^2=90$, corresponding to the co-ordinates (0,9.4868) and it matches the image given.
