Answer
Vertex = (4, -1)
Work Step by Step
x = 3$y^{2}$ + 6y + 7
x = 3[ $y^{2}$ + 2y + $\frac{7}{3}$ ]
x = 3[ $(y+1)^{2}$ - 1 + $\frac{7}{3}$ ]
x = 3[ $(y+1)^{2}$ + $\frac{4}{3}$ ]
x = 3$(y+1)^{2}$ + 4
Thus vertex = (4, -1)
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