## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 13 - Section 13.1 - The Parabola and the Circle - Exercise Set: 16

Vertex = (4, -1)

#### Work Step by Step

x = 3$y^{2}$ + 6y + 7 x = 3[ $y^{2}$ + 2y + $\frac{7}{3}$ ] x = 3[ $(y+1)^{2}$ - 1 + $\frac{7}{3}$ ] x = 3[ $(y+1)^{2}$ + $\frac{4}{3}$ ] x = 3$(y+1)^{2}$ + 4 Thus vertex = (4, -1)

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.