Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Section 13.1 - The Parabola and the Circle - Exercise Set: 16

Answer

Vertex = (4, -1)
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Work Step by Step

x = 3$y^{2}$ + 6y + 7 x = 3[ $y^{2}$ + 2y + $\frac{7}{3}$ ] x = 3[ $(y+1)^{2}$ - 1 + $\frac{7}{3}$ ] x = 3[ $(y+1)^{2}$ + $\frac{4}{3}$ ] x = 3$(y+1)^{2}$ + 4 Thus vertex = (4, -1)
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