Answer
$\frac{1}{2}log_{5}y$
Work Step by Step
We know that $log_{b}x^{r}=rlog_{b}x$ (where $x$ and $b$ are positive real numbers, $b\ne1$, and $r$ is a real number).
Therefore, $log_{5}\sqrt y=log_{5}y^{\frac{1}{2}}=\frac{1}{2}log_{5}y$.
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