#### Answer

$2^{5}=32$

#### Work Step by Step

We know that if $b\gt0$ and $b\ne1$, then $y=log_{b}x$ is equivalent to $x=b^{y}$ (where $x\gt0$ and $y$ is a real number).
Therefore, $log_{2}32=5$ can be written as the exponential equation $2^{5}=32$.

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$2^{5}=32$

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