Answer
$\frac{x-4}{2}$
Work Step by Step
4$\frac{x^2-8x+16}{2x-8}$
$-4\times-4=16, -4+-4=-8$
$=\frac{(x-4)(x-4)}{2x-8}$
$=\frac{(x-4)^2}{2(x-4)}$
$=\frac{x-4}{2}$
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