Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.5 - Logarithmic Functions - Exercise Set - Page 876: 87



Work Step by Step

4$\frac{x^2-8x+16}{2x-8}$ $-4\times-4=16, -4+-4=-8$ $=\frac{(x-4)(x-4)}{2x-8}$ $=\frac{(x-4)^2}{2(x-4)}$ $=\frac{x-4}{2}$
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