## Algebra: A Combined Approach (4th Edition)

$\frac{x-4}{2}$
4$\frac{x^2-8x+16}{2x-8}$ $-4\times-4=16, -4+-4=-8$ $=\frac{(x-4)(x-4)}{2x-8}$ $=\frac{(x-4)^2}{2(x-4)}$ $=\frac{x-4}{2}$