## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 12 - Section 12.5 - Logarithmic Functions - Exercise Set - Page 875: 51

#### Answer

$x=-3$

#### Work Step by Step

We know that if $b\gt0$ and $b\ne1$, then $y=log_{b}x$ is equivalent to $x=b^{y}$ (where $x\gt0$ and $y$ is a real number). Therefore, $log_{2}\frac{1}{8}=x$ is equivalent to $2^{x}=\frac{1}{8}$. Therefore, $x=-3$, because $2^{-3}=\frac{1}{2^{3}}=\frac{1}{8}$.

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