## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 12 - Section 12.1 - The Algebra of Functions - Practice - Page 840: 3

#### Answer

$\textbf{a.}\sqrt {x+1}$ $\textbf{b.}\sqrt x+1$

#### Work Step by Step

$f(x)=\sqrt x$ and $g(x)=x+1$ \begin{align} \textbf{a.}(f\bullet g)(x)&=f(g(x))\\&=f(x+1)\\&=\sqrt {x+1} \end{align} \begin{align} \textbf{b.}(g\bullet f)(x)&=g(f(x))\\&=g(\sqrt x)\\&=\sqrt x+1 \end{align}

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.