## Algebra: A Combined Approach (4th Edition)

x = 3+$\sqrt 7$ OR x = 3-$\sqrt 7$
$x^{2}$ - 6x = -2 $x^{2}$ - 6x + 9 = 7 $(x-3)^{2}$ = 7 x-3 = +/-$\sqrt 7$ x = 3+$\sqrt 7$ or x = 3-$\sqrt 7$