Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.6 - Further Graphing of Quadratic Functions - Exercise Set - Page 823: 58

Answer

a) 185.312 million metric tons b) maximum c) 2013 d) 186.82 million metric tons

Work Step by Step

a) $2018-2000=18$ $f(x)=-.072x^2+1.93x+173.9$ $f(18)=-.072*18^2+1.93*18+173.9$ $f(18)=-.072*324+34.74+173.9$ $f(18)=-23.328+34.74+173.9$ $f(18)=185.312$ b) The coefficient of the $x^2$ term is negative, so the graph opens down. Since the graph opens down, the vertex of the graph is the graph’s maximum point. c) $f(x)=-.072x^2+1.93x+173.9$ The highest (or lowest) point on a graph is found using the vertex of a graph. The vertex of the graph has the equation $x=-b/2a$. $a=-.072$, $b=1.93$, $c=173.9$ $x=-b/2a$ $x=-1.93/2*-.072$ $x=1.93/.144$ $x=13.4$ Rounded to the nearest number, $x=13$ $13+2000=2013$ d) $f(x)=-.072x^2+1.93x+173.9$ $f(13)=-.072*13^2+1.93*13+173.9$ $f(13)=-.072*169+25.09+173.9$ $f(13)=-12.168+198.99$ $f(13)=186.822$
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