Answer
$(3,0)$
Work Step by Step
$f(x)=(x-3)^2$
$(x-3)^2=(x-3)(x-3)$
$(x-3)^2=x^2-6x+9$
$a=1$, $b=-6$, $c=9$
Vertex: $x=-b/2a$
$x=-(-6)/2*1$
$x=6/2$
$x=3$
$f(x)=(x-3)^2$
$f(3)=(3-3)^2$
$f(3)=0^2$
$f(3)=0$
$(3,0)$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 11 - Section 11.6 - Further Graphing of Quadratic Functions - Exercise Set - Page 822: 40
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