Answer
C
Work Step by Step
$f(x)=x^2+4x+3$
$f(x)=(x^2+4x)+3$
$f(x)=(x^2+4x+(4/2)^2)+3-(4/2)^2$
$f(x)=(x^2+4x+(2)^2)+3-(2)^2$
$f(x)=(x^2+4x+4)+3-4$
$f(x)=(x+2)^2-1$
Vertex is $(-2,-1)$, which matches graph C
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