Answer
x=5
Work Step by Step
x - 3 = $\sqrt {x-1}$
We then square the entire equation
$x^{2}$ - 6x + 9 = x -1
$x^{2}$ -7x +10 = 0
We can factor this
(x-5)(x-2) = 0
Thus, x is either 5 or 2.
CHECK for x=5
5-3 = $\sqrt 4$
2=2
Thus, x can be 5
CHECK for x=2
2-3 = 1
-1 = 1 (rejected)
x cannot be 2
