Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Practice: 1

Answer

x=5

Work Step by Step

x - 3 = $\sqrt {x-1}$ We then square the entire equation $x^{2}$ - 6x + 9 = x -1 $x^{2}$ -7x +10 = 0 We can factor this (x-5)(x-2) = 0 Thus, x is either 5 or 2. CHECK for x=5 5-3 = $\sqrt 4$ 2=2 Thus, x can be 5 CHECK for x=2 2-3 = 1 -1 = 1 (rejected) x cannot be 2
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