## Algebra: A Combined Approach (4th Edition)

x - 3 = $\sqrt {x-1}$ We then square the entire equation $x^{2}$ - 6x + 9 = x -1 $x^{2}$ -7x +10 = 0 We can factor this (x-5)(x-2) = 0 Thus, x is either 5 or 2. CHECK for x=5 5-3 = $\sqrt 4$ 2=2 Thus, x can be 5 CHECK for x=2 2-3 = 1 -1 = 1 (rejected) x cannot be 2