Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.2 - Solving Quadratic Equations by Completing the Square - Practice - Page 772: 8

Answer

7 feet

Work Step by Step

$x^2+(x+8)^2=20^2$ $x^2+x^2+8x+8x+8*8=400$ $2x^2+16x+64=400$ $(2x^2+16x+64=400)/2$ $x^2+8x+32=200$ $x^2+8x-168=0$ $x=(-b±\sqrt {b^2-4ac} )/2a$ $x=(-8±\sqrt {8^2-4*1*-168} )/2*1$ $x=(-8±\sqrt {64+4*1*168})/2$ $x=(-8±\sqrt {64+672})/2$ $x=(-8±\sqrt {736})/2$ $x=(-8±\sqrt {720+16})/2$ $x=(-8±\sqrt {180*4+4*4})/2$ $x=(-8±\sqrt {184*4})/2$ $x=(-8±2\sqrt {184})/2$ $x=(-4±\sqrt {184})$ We are talking about distance, so we can't have a negative distance. Thus, we want the positive square root. $x=-4+\sqrt {184}$ $x=-4+13.56$ $x=9.565$ $9.565+9.565+8-20$ $19.13+8-20$ $27.13-20$ $7.13$
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