# Chapter 11 - Section 11.2 - Solving Quadratic Equations by Completing the Square - Practice - Page 769: 1

The solution set is ${-\frac{5}{2},-2}$

#### Work Step by Step

To solve we must use the quadratic equation ($\frac{-b\pm\sqrt{ b^{2} - 4ac}}{2a}$) where a = 2, b = 9, c = 10. So substitute $\frac{-9\pm\sqrt{ 9^{2} - 4(2)(10)}}{2(2)}$=.. $\frac{-9\pm\sqrt{1}}{4}$=.. $\frac{-9\pm1}{4}$ so the two solutions are x = $\frac{-9+1}{4}$ = -2 x = $\frac{-9-1}{4} = -\frac{10}{4} = -\frac{5}{2}$

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