#### Answer

The solution set is ${-\frac{5}{2},-2}$

#### Work Step by Step

To solve we must use the quadratic equation ($\frac{-b\pm\sqrt{ b^{2} - 4ac}}{2a}$) where a = 2, b = 9, c = 10. So substitute
$\frac{-9\pm\sqrt{ 9^{2} - 4(2)(10)}}{2(2)}$=..
$\frac{-9\pm\sqrt{1}}{4}$=..
$\frac{-9\pm1}{4}$
so the two solutions are
x = $\frac{-9+1}{4}$ = -2
x = $\frac{-9-1}{4} = -\frac{10}{4} = -\frac{5}{2}$