Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.2 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 780: 88

Answer

a) 55.6 million b) 94.4 million c) 2015-2016

Work Step by Step

a) $2010-2009=1$ $c(x)=-.4x^2+21x+35$ $c(1)=-.4*1^2+21*1+35$ $c(1)=-.4+21+35$ $c(1)=55.6$ b) $2012-2009=3$ $c(x)=-.4x^2+21x+35$ $c(3)=-.4*3^2+21*3+35$ $c(3)=-.4*9+63+35$ $c(3)=-3.6+98$ $c(3)=94.4$ c) $c(x)=-.4x^2+21x+35$ $150=-.4x^2+21x+35$ $0=-.4x^2+21x-115$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-21±\sqrt {21^2-4*(-.4)*(-115)})/2*(-.4)$ $x=(-21±\sqrt {441-1.6*115})/-.8$ $x=(-21±\sqrt {441-184})/-.8$ $x=(-21±\sqrt {257})/-.8$ $x=(-21±16.03)/-.8$ $x=(-21±16.03)/-.8$ $x=(-21+16.03)/-.8$ $x=-5.03/-.8$ $x=6.2875$ $x=(-21±16.03)/-.8$ $x=(-21-16.03)/-.8$ $x=-37.03/-.8$ $x=46.2875$ We want the lower value for $x$. $x=6.2$ $2009+6.2=2015.2$
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