Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.2 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 777: 53

Answer

4.828 cm, 4.828 cm, 6.828 cm

Work Step by Step

$x^2+x^2=(x+2)^2$ $2x^2=x^2+2*x+x*2+2*2$ $2x^2=x^2+4x+4$ $x^2-4x-4=0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-(-4)±\sqrt {(-4)^2-4*1*-4})/2*1$ $x=(4±\sqrt {16+16})/2$ $x=(4±\sqrt {2*16})/2$ $x=(4±4\sqrt {2})/2$ $x=(2±2\sqrt {2})$ We are talking about distances, so we want the positive square root. $x=(2+2\sqrt {2})$ $x=2+2*1.414$ $x=2+2.828$ $x=4.828$
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