## Algebra: A Combined Approach (4th Edition)

$x = (\frac{1+2i}{3}, \frac{1-2i}{3})$
$(3x-1)^2 = -4$ $3x-1 = ±\sqrt -4$ (Use Square root Property) $3x-1= ± 2i$ (Simplify the radical) $3x = 1 ± 2i$ (Add 1 to both sides) $x=\frac{1±2i}{3}$ (Divide by 3 on both sides) The solution set is $(\frac{1 + 2i}{3}, \frac{1-2i}{3})$ Note : Root of a negative number is a complex number and is represented by 'i'