## Algebra: A Combined Approach (4th Edition)

$x = (3\sqrt 5, -3\sqrt 5)$
$x^{2}$ = 45 $x = ± \sqrt45$ (Use the square root property) $x = ±5\sqrt 2$ (Simplify the radical) Check- 1. Let $x = 3\sqrt 5$ $x^{2} = 45$ $(3\sqrt 5)^{2}$ could be $45$ $9\times5$ could be $45$ $45 = 45$ Hence, true. 2. Let $x = -3\sqrt 5$ $x^{2} = 45$ $(-3\sqrt 5)^{2}$ could be $45$ $9\times5$ could be $45$ $45 = 45$ Hence, true. Therefore, the solution set is $x = (3\sqrt 5, -3\sqrt 5)$