Answer
$x = (3\sqrt 5, -3\sqrt 5)$
Work Step by Step
$x^{2}$ = 45
$x = ± \sqrt45 $ (Use the square root property)
$x = ±5\sqrt 2$ (Simplify the radical)
Check-
1. Let $ x = 3\sqrt 5 $
$x^{2} = 45$
$(3\sqrt 5)^{2}$ could be $45 $
$9\times5$ could be $45$
$45 = 45$ Hence, true.
2. Let $ x = -3\sqrt 5 $
$x^{2} = 45$
$(-3\sqrt 5)^{2}$ could be $45 $
$9\times5$ could be $45$
$45 = 45$ Hence, true.
Therefore, the solution set is $x = (3\sqrt 5, -3\sqrt 5)$
