#### Answer

The solutions are complex.

#### Work Step by Step

The equation presented is $(2y-5)^{2} + 7 = 3$. The first step of solving this equation is to subtract seven from both sides, leaving us with $(2y-5)^{2} = -4$. Next, one would take the square root of both sides; however, as $\sqrt {-4}$ is imaginary, the solutions to the equation are complex.