Answer
$x=-\frac{16}{5}$ or $x=1$
Work Step by Step
We simplify as follows:
$5(x+3)^{2}-19(x+3)=4$
Let $m=x+3$
$5m^{2}-19m=4$
$5m^{2}-19m-4=0$
$(5m+1)(m-4)=0$
$5m+1=0$ or $m-4=0$
$5m=-1$ or $m=4$
$m=-\frac{1}{5}$ or $m=4$
$x+3=-\frac{1}{5}$ or $x+3=4$
$x=-\frac{16}{5}$ or $x=1$
