Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Review: 12

Answer

One real solution

Work Step by Step

Since the discriminant ($b^2-4ac$) is equal to 0, the quadratic equations has one real solution: $\dfrac{-b\pm \sqrt{b^2-4ac}}{2a} = \dfrac{-b\pm \sqrt{0}}{2a} = \dfrac{-b\pm 0}{2a} = -\dfrac{b}{2a}$
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