Answer
$\frac{\sqrt[3] 5}{3x}$
Work Step by Step
$\sqrt[3] {\frac{5}{27x^{3}}}=\frac{\sqrt[3] 5}{\sqrt[3] {27x^{3}}}=\frac{\sqrt[3] 5}{\sqrt[3] {3^{3}\times x^{3}}}=\frac{\sqrt[3] 5}{\sqrt[3] {3^{3}}\times \sqrt[3] {x^{3}}}=\frac{\sqrt[3] 5}{3\times x}=\frac{\sqrt[3] 5}{3x}$
