#### Answer

$-1$

#### Work Step by Step

$i^{50}=i^{48}\times i^{2}=(i^{4})^{12}\times i^{2}$
As $i^{4}=1$ and $i^{2}=-1$,
$(i^{4})^{12}\times i^{2}=(1)^{12}\times (-1)=1\times-1=-1$.
Therefore, $i^{50}=-1$.

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$-1$

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