Answer
$\dfrac{6+8i}{3i}=\dfrac{8}{3}-2i$
Work Step by Step
$\dfrac{6+8i}{3i}$
Multiply the numerator and the denominator of this expression by the complex conjugate of the denominator:
$\dfrac{6+8i}{3i}=\dfrac{6+8i}{3i}\cdot\dfrac{-3i}{-3i}=\dfrac{-3i(6+8i)}{-9i^{2}}=\dfrac{-18i-24i^{2}}{-9i^{2}}=...$
Substitute $i^{2}$ with $-1$ and simplify:
$...=\dfrac{-18i-24(-1)}{-9(-1)}=\dfrac{24-18i}{9}=\dfrac{24}{9}-\dfrac{18}{9}i=\dfrac{8}{3}-2i$
