Answer
$16-8\sqrt{7x}+7x$
Work Step by Step
$(4-\sqrt {7x})^2$
$(4-\sqrt {7x})(4-\sqrt {7x})$
$4*4+4*(-\sqrt {7x})+(-\sqrt {7x})*4+(-\sqrt {7x})(-\sqrt {7x})$
$16-4\sqrt{7x}-4\sqrt{7x}+\sqrt{7x*7x}$
$16-8\sqrt{7x}+7x$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.6 - Radical Equations and Problem Solving - Vocabulary and Readiness Check - Page 728: 4
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