Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.6 - Radical Equations and Problem Solving - Practice - Page 726: 6

Answer

$b=3\sqrt3$ cm

Work Step by Step

$3^2+b^2=6^2$ $9+b^2=36$ $b^2=27$ $\sqrt {b^2} =\sqrt {27}$ $b=\sqrt {27}$ $b=\sqrt {3*3*3}$ $b=3\sqrt3$
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