Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.6 - Radical Equations and Problem Solving - Exercise Set - Page 729: 38



Work Step by Step

$\sqrt {3y+6}=\sqrt {7y-6}$ $(\sqrt {3y+6})^2=(\sqrt {7y-6})^2$ $3y+6=7y-6$ $3y+12=7y$ $3y+12-3y=7y-3y$ $12=4y$ $12/4=4y/4$ $3=y$ $\sqrt {3y+6}=\sqrt {7y-6}$ $\sqrt {3*3+6}=\sqrt {7*3-6}$ $\sqrt {9+6}=\sqrt {21-6}$ $\sqrt {15}=\sqrt {15}$ (true)
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