Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.4 - Adding, Subtracting, and Multiplying Radical Expressions - Practice: 14

Answer

$52-14\sqrt 3$

Work Step by Step

Step 1: The expression to be used here is, $(a-b)^{2}=a^{2}-2ab + b^{2}$ Step 2: Accordingly, the expression in the question becomes $(\sqrt 3-7)^{2}= (\sqrt 3)^{2}- 2(\sqrt 3)(7) + 7^{2}$ Step 3: Simplifying, $(\sqrt 3)^{2}- 2(\sqrt 3)(7) + 7^{2}$= $3-14\sqrt 3+49= 52-14\sqrt 3$
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