Answer
$\frac{5\sqrt {7}}{2x}$
Work Step by Step
$\sqrt \frac{28}{{x^2}}+\sqrt \frac{7}{{4x^2}}$
$\frac{2\sqrt {7}}{x}+\frac{\sqrt {7}}{2x}$ The LCD is 2x.
$\frac{4\sqrt {7}}{2x}+\frac{\sqrt {7}}{2x}$
$\frac{5\sqrt {7}}{2x}$
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