Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.3 - Simplifying Radical Expressions - Practice - Page 699: 18

Answer

$\dfrac{4}{3}\sqrt {y}$

Work Step by Step

$\dfrac{\sqrt {80y}}{3\sqrt 5}=\dfrac{1}{3}\sqrt {\dfrac{80y}{5}}=\dfrac{1}{3}\sqrt {16y}=\dfrac{4}{3}\sqrt {y}$
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