Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.3 - Simplifying Radical Expressions - Practice - Page 697: 9


$\dfrac{\sqrt[5] {7}}{2x}$

Work Step by Step

$\sqrt[5] {\dfrac{7}{32x^{5}}}=\dfrac{\sqrt[5] {7}}{\sqrt[5] {32x^{5}}}=\dfrac{\sqrt[5] {7}}{2x}$
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