#### Answer

$-2$

#### Work Step by Step

Remember that the index is the denominator of the exponent.
$-16^{1/4}$
$-\sqrt[4]{16}$
$-2$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$-2$

Remember that the index is the denominator of the exponent.
$-16^{1/4}$
$-\sqrt[4]{16}$
$-2$

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