Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.1 - Radical Expressions and Radical Functions - Exercise Set - Page 688: 113


11181 meters per second

Work Step by Step

Given: $v=\sqrt{\dfrac{2Gm}{r}}$ $G=6.67\times10^{-11}m^3/kg\bullet s^2$. mass of Earth is $5.97\times10^{24}$ kg radius of Earth is $6.37\times10^6$ m Find escape velocity for Earth in meters per second. Plug in given information into the formula and solve: $v=\sqrt{\dfrac{2(6.67\times10^{-11}m^3/kg\bullet s^2)(5.97\times10^{24}kg)}{6.37\times10^6m}}$ $v=\sqrt{\dfrac{7.96398\times10^{14}m^3/s^2}{6.37\times10^6m}}$ $v=\sqrt{125023233.9m^2/s^2}$ $v=11181.37889$ m/s Round answer to the nearest whole number: The escape velocity for Earth is 11181 meters per second.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.