#### Answer

$\sqrt{\frac{9}{25}}=\frac{3}{5}, -\frac{3}{5}$

#### Work Step by Step

Since $(\frac{3}{5})^2=\frac{9}{25}$ and $(-\frac{3}{5})^2=\frac{9}{25}$ the square roots of $\frac{9}{25}$ are $\frac{3}{5},-\frac{3}{5}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\sqrt{\frac{9}{25}}=\frac{3}{5}, -\frac{3}{5}$

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