Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 65

Answer

$3\sqrt[3] 6$

Work Step by Step

$\sqrt[3] {162}=\sqrt[3] {81\times2}=\sqrt[3] {27\times3\times2}=\sqrt[3] {27\times6}=\sqrt[3] {27}\sqrt[3] 6=3\sqrt[3] 6$
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