## Algebra: A Combined Approach (4th Edition)

(a) $7x-3$ (b) $-3x+11$ (c) $6x-14$
Part (a) =$2(x-3)+ (5x+3)$ =$2x-6+5x+3$ =$2x+5x-6+3$ =$7x-3$ Part (b) =$4(3x+2)-3(5x-1)$ =$12x+8-15x+3$ =$12x-15x+8+3$ =$-3x+11$ Part (c) =$7x+2(x-7)-3x$ =$7x+2x-14-3x$ =$7x+2x-3x-14$ =$6x-14$