Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 1 - Section 1.6 - Multiplying and Dividing Real Numbers - Practice: 16

Answer

(a) $\frac{1}{3}$ (b) 126 (c) 2

Work Step by Step

Substituting $x=-1$ and $y=-5$ in each of the three expressions, Part (a) $\frac{3y}{45x}=\frac{3(-5)}{45(-1)}=\frac{-15}{-45}=\frac{1}{3}$ Part (b) $x^{2}-y^{3}=(-1)^{2}-(-5)^{3}=(1)-(-125)=1+125=126$ Part (c) $\frac{x+y}{3x}=\frac{-1-5}{3(-1)}=\frac{-6}{-3}=2$
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