Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 1 - Section 1.5 - Subtracting Real Numbers - Practice: 8

Answer

a.$\frac{1}{3}$ b.$5$

Work Step by Step

$x=1$ $y=-4$ a.$\frac{x-y}{14+x}$ Substitute and then simplify. $\frac{1-(-4)}{14+1}=\frac{5}{15}=\frac{1}{3}$ b.Do likewise for part b. $x^{2}-y$ $1^{2}-(-4)=1+4=5$
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