Algebra: A Combined Approach (4th Edition)

a.$\frac{1}{3}$ b.$5$
$x=1$ $y=-4$ a.$\frac{x-y}{14+x}$ Substitute and then simplify. $\frac{1-(-4)}{14+1}=\frac{5}{15}=\frac{1}{3}$ b.Do likewise for part b. $x^{2}-y$ $1^{2}-(-4)=1+4=5$