## Algebra: A Combined Approach (4th Edition)

$\frac{9}{5}\times\frac{1}{3}-\frac{1}{3}=\frac{4}{15}$
Recall the order of operations, "Parentheses first, Exponents second, Multiplication and Division third(from left to right), and Addition and Subtraction fourth(from left to right)". So, first we do, $\frac{9}{5}\times\frac{1}{3}$ ,giving us $\frac{9}{15}$ Then, we see that the remaining two fractions do not share the base but must be subtracted, so we must find the least common denominator. In this case, we multiply the numerator and denominator by 5 for the fraction $\frac{1}{3}$ so that it may have the least common denominator of 15. $\frac{9}{15}-\frac{1}{3}\times\frac{5}{5}=\frac{9}{15}-\frac{5}{15}=\frac{4}{15}$