## Algebra: A Combined Approach (4th Edition)

Combine like terms: $\frac{4}{5}y$ + 1 + $\frac{6}{5}y$ + 2 = ($\frac{4}{5}y$ + $\frac{6}{5}y$) + (1 + 2) = $\frac{10}{5}y$ + 3 = 2y + 3