## Algebra: A Combined Approach (4th Edition)

We are given : Xscl = 5 and Yscl = 10 We count 6 tick marks horizontally from the origin, to the right, so $Xmax = 5*6 = 30$. To the left, horizontally, we count 4 tick marks, so $Xmin = 4*5 = 20$. Similarly, we count 5 tick marks upwards and 3 downwards so $Ymax = 5*10 = 50$ and $Ymin = 3*10 = 30$.