Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix B - Exercise Set - Page 980: 25

Answer

$x = \frac{1}{6}$

Work Step by Step

$\frac{x}{2}+\frac{2}{3} = \frac{3}{4} \lt=\gt \frac{x}{2} = \frac{1}{12} \lt=\gt x = \frac{1}{6}$
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