# Appendix A - Practice: 3

Practice 3 (Answer) $(\,7xy^{-2})\,^{-2}$ =$\frac{y^4}{49x^2}$

#### Work Step by Step

Practice 3 (Solution) $(\,7xy^{-2})\,^{-2}$ =$7^{-2}x^{-2}(\,y^{-2})\,^{-2}$ (Power of a product) =$7^{-2}x^{-2}y^4$ (Power rule) =$\frac{y^4}{49x^2}$ (Negative exponent)

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