Answer
Practice 3 (Answer)
$(\,7xy^{-2})\,^{-2}$
=$\frac{y^4}{49x^2}$
Work Step by Step
Practice 3 (Solution)
$(\,7xy^{-2})\,^{-2}$
=$7^{-2}x^{-2}(\,y^{-2})\,^{-2}$ (Power of a product)
=$7^{-2}x^{-2}y^4$ (Power rule)
=$\frac{y^4}{49x^2}$ (Negative exponent)