Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix A - Exercise Set: 17

Answer

Appendix A - Ex. Set : 17 (Answer) $(\frac{2a^{-2}b^5}{4a^2b^7})^{-2}$ $= 4a^8b^4$

Work Step by Step

Appendix A - Ex. Set : 17 (Solution) $(\frac{2a^{-2}b^5}{4a^2b^7})^{-2}$ $= \frac{(2a^{-2}b^5)^{-2}}{(4a^2b^7)^{-2}}$ (Power of a quotient) $= \frac{2^{-2}a^4b^{-10}}{(2^2)^{-2}a^{-4}b^{-14}}$ (Power rule) $= 2^{-2-(-4)}a^{4-(-4)}b^{-10-(-14)}$ (Quotient rule) $= 2^2a^8b^4$ $= 4a^8b^4$
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