Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Entry-Level Assessment - Page xxxvi: 2

Answer

$F$

Work Step by Step

To solve the quadratic equation, we first need to factor the expression. In order to do so, we first find two numbers that add to $2$ (the coefficient of the $x$-term) and multiply to $–3$ (the constant term). These numbers are $3$ and $–1$, because $3 + (–1) = 2$ and $3(–1) = –3$. Therefore: $x^{2}+2x–3 = (x + 3)(x– 1)$ And our equation is now: $(x + 3)(x– 1) = 0$ This means that either $x + 3 = 0$ or $ x – 1 = 0$ (by Zero Product Property). Solving each of these for $x$, our solutions become: $x = –3$ and $x = 1$
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